Yes of course,
From Wkipedia:
"As rust has higher volume than the originating mass of iron, its buildup may force apart adjacent parts - a phenomenon known as rust smacking."
The smacking formula is as follows; again from Wikipedia:
"Fe(s) -> Fe2+(aq) + 2e-
"harply, but this is of no consequence since OH- ions are always present, even in pure water.) The cations then react with the OH- or even the H+ ions and dissolved oxygen to form a variety of compounds, which constitute rust:
Fe2+(aq) + 2OH-(aq) -> Fe(OH)2(s)
4Fe2+(aq) + 4H+(aq) + O2(aq) -> 4Fe3+(aq) + 2H2O(l)
Fe3+(aq) + 3OH-(aq) -> Fe(OH)3(s)
From the above equations, it is seen that the pH and amount of dissolved oxygen can affect the outcome of the reactions. In water with limited dissolved oxygen Fe3O4(s) is formed, which is a black solid and commonly called lodestone:
6Fe2+(aq) + O2(aq) + 12OH-(aq) -> 2Fe3O4(s) + 6H2O(l)
The porous Fe(OH)3 rust can slowly disintegrate into a crystallized form, which is the familiar red-brown rust:
2Fe(OH)3(s) -> Fe2O3�H2O(s) + 2H2O(l)
Iron oxide (FeO) can also be formed. The presence of other ions, such as calcium or calcium carbonates reacts with the iron hydroxides and iron oxides to form a variety of precipitates. Other metals corrode via similar chemical processes."
Now we got the other variable you called "tin-lead-something" to put into the equation:
The short answer to this is: yes, it will take some time, more than a while...
Best Regards, Mika
Ps. If you are going to solder something to be exposed "outside", concider to glue the whole thing. Maybe some other nice fellows at this forum can tell you how. Ds.
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